Series-1
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(1 + 1/2 + 1/3 +......+ 1/n)
#include<stdio.h>
#include<conio.h>
void main()
{
int i,n;
float s=0;
clrscr();
printf("Enter the value:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
s+=1/i;
}
printf("Sum is %d",s);
getch();
}
OUTPUT:
Enter the value:4
2.0833333333
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